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In StockAdd to CartReformatting the input :
Changes made to your input should not affect the solution:
(1): 'x2' was replaced by 'x^2'. 1 more similar replacement(s).
(1): 'x2' was replaced by 'x^2'. 1 more similar replacement(s).
Step 1 :
Equation at the end of step 1 :
Equation at the end of step 2 :
Step 3 :
Checking for a perfect cube :
Trying to factor by pulling out :
9 X 2 3 Fraction
3.2 Factoring: 9x3+9x2-x-1
Thoughtfully split the expression at hand into groups, each group having two terms :
Group 1: -x-1
Group 2: 9x3+9x2
Pull out from each group separately :
Group 1: (x+1) • (-1)
Group 2: (x+1) • (9x2)
-------------------
Add up the two groups :
(x+1) • (9x2-1)
Which is the desired factorization
Thoughtfully split the expression at hand into groups, each group having two terms :
Group 1: -x-1
Group 2: 9x3+9x2
Pull out from each group separately :
Group 1: (x+1) • (-1)
Group 2: (x+1) • (9x2)
-------------------
Add up the two groups :
(x+1) • (9x2-1)
Which is the desired factorization
Amazing 2 9 9 X 9
Trying to factor as a Difference of Squares :
Amazing 2 9 9 X 9 9 Worsted Wool Rugs
3.3 Factoring: 9x2-1
Theory : A difference of two perfect squares, A2 - B2can be factored into (A+B) • (A-B)
Proof : (A+B) • (A-B) =
A2 - AB + BA - B2 =
A2- AB + AB - B2 =
A2 - B2
Note : AB = BA is the commutative property of multiplication.
Note : - AB + AB equals zero and is therefore eliminated from the expression.
Check : 9 is the square of 3
Check : 1 is the square of 1
Check : x2is the square of x1
Factorization is : (3x + 1) • (3x - 1)
Theory : A difference of two perfect squares, A2 - B2can be factored into (A+B) • (A-B)
Proof : (A+B) • (A-B) =
A2 - AB + BA - B2 =
A2- AB + AB - B2 =
A2 - B2
Note : AB = BA is the commutative property of multiplication.
Note : - AB + AB equals zero and is therefore eliminated from the expression.
Check : 9 is the square of 3
Check : 1 is the square of 1
Check : x2is the square of x1
Factorization is : (3x + 1) • (3x - 1)